Problem Overview
We evaluate the shear force distribution V ( x ) = d M d x V(x) = \frac{dM}{dx} V ( x ) = d x d M â on a structural highway bridge girder given the bending moment equation:
M ( x ) = 48 x â 16 ( x + 4 ) â 1 2 â 2 x 2 M(x) = 48x - 16(x + 4)^{-\frac{1}{2}} - 2x^2 M ( x ) = 48 x â 16 ( x + 4 ) â 2 1 â â 2 x 2
Step-by-Step Mathematical Solution
Step 1: Pre-Process Bending Moment Expression
Express the radical denominator term using rational and negative exponents:
16 x + 4 = 16 ( x + 4 ) â 1 2 \frac{16}{\sqrt{x + 4}} = 16(x + 4)^{-\frac{1}{2}} x + 4 â 16 â = 16 ( x + 4 ) â 2 1 â
M ( x ) = 48 x â 16 ( x + 4 ) â 1 2 â 2 x 2 M(x) = 48x - 16(x + 4)^{-\frac{1}{2}} - 2x^2 M ( x ) = 48 x â 16 ( x + 4 ) â 2 1 â â 2 x 2
Step 2: Differentiate to Obtain Shear Force V ( x ) V(x) V ( x )
Differentiate term-by-term using the Power Rule:
V ( x ) = d M d x = 48 ( 1 ) â 16 ( â 1 2 ( x + 4 ) â 3 2 ) â 2 ( 2 x ) V(x) = \frac{dM}{dx} = 48(1) - 16\left(-\frac{1}{2}(x + 4)^{-\frac{3}{2}}\right) - 2(2x) V ( x ) = d x d M â = 48 ( 1 ) â 16 ( â 2 1 â ( x + 4 ) â 2 3 â ) â 2 ( 2 x )
V ( x ) = 48 + 8 ( x + 4 ) â 3 2 â 4 x V(x) = 48 + 8(x + 4)^{-\frac{3}{2}} - 4x V ( x ) = 48 + 8 ( x + 4 ) â 2 3 â â 4 x
Step 3: Post-Process and Evaluate at Specified Coordinates
Convert the negative fractional exponent back into radical form:
V ( x ) = 48 + 8 ( x + 4 ) 3 â 4 x V(x) = 48 + \frac{8}{\sqrt{(x + 4)^3}} - 4x V ( x ) = 48 + ( x + 4 ) 3 â 8 â â 4 x
At Support Coordinate x = 0 Â m x = 0\text{ m} x = 0 Â m :
V ( 0 ) = 48 + 8 ( 0 + 4 ) 3 â 4 ( 0 ) = 48 + 8 64 = 48 + 8 8 = 49 Â kN V(0) = 48 + \frac{8}{\sqrt{(0 + 4)^3}} - 4(0) = 48 + \frac{8}{\sqrt{64}} = 48 + \frac{8}{8} = 49\text{ kN} V ( 0 ) = 48 + ( 0 + 4 ) 3 â 8 â â 4 ( 0 ) = 48 + 64 â 8 â = 48 + 8 8 â = 49 Â kN
At Coordinate x = 5 Â m x = 5\text{ m} x = 5 Â m :
V ( 5 ) = 48 + 8 ( 5 + 4 ) 3 â 4 ( 5 ) = 48 + 8 9 3 â 20 = 28 + 8 27 â 28.296 Â kN V(5) = 48 + \frac{8}{\sqrt{(5 + 4)^3}} - 4(5) = 48 + \frac{8}{\sqrt{9^3}} - 20 = 28 + \frac{8}{27} \approx 28.296\text{ kN} V ( 5 ) = 48 + ( 5 + 4 ) 3 â 8 â â 4 ( 5 ) = 48 + 9 3 â 8 â â 20 = 28 + 27 8 â â 28.296 Â kN
Engineering Conclusion
By algebraically converting the root term into a negative fractional exponent prior to differentiation, structural engineers directly calculate shear force diagrams without tedious numerical approximations. The girder experiences maximum shear (49 Â kN 49\text{ kN} 49 Â kN ) at the left abutment support (x = 0 x = 0 x = 0 ), guiding the required thickness and bolt spacing of the web stiffeners.