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Beam Deflection and Shearing Force (Civil Engineering) Solution

Problem Overview

We evaluate the shear force distribution V(x)=dMdxV(x) = \frac{dM}{dx} on a structural highway bridge girder given the bending moment equation:

M(x)=48x−16(x+4)−12−2x2M(x) = 48x - 16(x + 4)^{-\frac{1}{2}} - 2x^2


Step-by-Step Mathematical Solution

Step 1: Pre-Process Bending Moment Expression

Express the radical denominator term using rational and negative exponents:

16x+4=16(x+4)−12\frac{16}{\sqrt{x + 4}} = 16(x + 4)^{-\frac{1}{2}}
M(x)=48x−16(x+4)−12−2x2M(x) = 48x - 16(x + 4)^{-\frac{1}{2}} - 2x^2

Step 2: Differentiate to Obtain Shear Force V(x)V(x)

Differentiate term-by-term using the Power Rule:

V(x)=dMdx=48(1)−16(−12(x+4)−32)−2(2x)V(x) = \frac{dM}{dx} = 48(1) - 16\left(-\frac{1}{2}(x + 4)^{-\frac{3}{2}}\right) - 2(2x)
V(x)=48+8(x+4)−32−4xV(x) = 48 + 8(x + 4)^{-\frac{3}{2}} - 4x

Step 3: Post-Process and Evaluate at Specified Coordinates

Convert the negative fractional exponent back into radical form:

V(x)=48+8(x+4)3−4xV(x) = 48 + \frac{8}{\sqrt{(x + 4)^3}} - 4x

  1. At Support Coordinate x=0 mx = 0\text{ m}:
    V(0)=48+8(0+4)3−4(0)=48+864=48+88=49 kNV(0) = 48 + \frac{8}{\sqrt{(0 + 4)^3}} - 4(0) = 48 + \frac{8}{\sqrt{64}} = 48 + \frac{8}{8} = 49\text{ kN}
  2. At Coordinate x=5 mx = 5\text{ m}:
    V(5)=48+8(5+4)3−4(5)=48+893−20=28+827≈28.296 kNV(5) = 48 + \frac{8}{\sqrt{(5 + 4)^3}} - 4(5) = 48 + \frac{8}{\sqrt{9^3}} - 20 = 28 + \frac{8}{27} \approx 28.296\text{ kN}

Engineering Conclusion

By algebraically converting the root term into a negative fractional exponent prior to differentiation, structural engineers directly calculate shear force diagrams without tedious numerical approximations. The girder experiences maximum shear (49 kN49\text{ kN}) at the left abutment support (x=0x = 0), guiding the required thickness and bolt spacing of the web stiffeners.