Core Definition
For any real argument x>0:
Natural Logarithm:
dxd[ln(x)]=x1
General Logarithm (Base a>0,a=1):
dxd[loga(x)]=xln(a)1
When layered with a differentiable inner function
u=g(x)>0, the
Chain Rule yields:
dxd[ln(u)]=u1dxdu=uu′anddxd[loga(u)]=uln(a)u′
Concept Explanation
1. Derivation via Implicit Differentiation
The derivative of ln(x) is established directly from the fact that y=ln(x) is the inverse of x=ey. Differentiating both sides implicitly with respect to x:
dxd[ey]=dxd[x]⟹eydxdy=1⟹dxdy=ey1
Because ey=x, substituting back gives dxdy=x1.
2. General Logarithm via Change of Base
By the Change of Base formula (see Logarithmic and Exponential Properties), loga(x)=ln(a)ln(x). Differentiating using the Constant Multiple Rule:
dxd[loga(x)]=ln(a)1⋅dxd[ln(x)]=ln(a)1⋅x1=xln(a)1
3. Logarithmic Pre-Processing: The Time-Saving Technique
Before applying calculus derivative rules, always expand the argument completely using fundamental logarithm properties (see Logarithmic and Exponential Properties and Negative and Rational Exponents):
- Product Property: ln(A⋅B)=ln(A)+ln(B)⟹dxd[ln(AB)]=AA′+BB′
- Quotient Property: ln(BA)=ln(A)−ln(B)⟹dxd[ln(BA)]=AA′−BB′
- Power Property: ln(Ak)=kln(A)⟹dxd[ln(Ak)]=kAA′
Differentiating the expanded sum of terms eliminates the need to execute cumbersome Quotient and Product rules inside uu′.
Engineering Applications
- Aerospace Engineering (Tsiolkovsky Rocket Equation): The rocket velocity formula v(m)=veln(m0/m)=veln(m0)−veln(m) is differentiated to determine the vehicle's acceleration dtdv=−mvedtdm during fuel burn (see Rocket Velocity Optimization via Rocket Equation (Aerospace Engineering)).
- Chemical Engineering (Acidity and pH Sensors): The pH of chemical solutions is tracked via pH=−log10(H+). Calculating rate of pH change dtd(pH)=−H+ln(10)1dtdH+ provides feedback for automated buffering valves (see Reaction Rate Kinematics and pH Buffering (Chemical Engineering)).
- Computer Science & Telecommunications (Entropy and Information): Shannon entropy and signal attenuation in communication channels depend on base-2 and natural logarithms.
Example Problems
Example 1: Differentiating with Pre-Processing
Differentiate h(x)=ln(x2+2xx2−x) for x>1.
Solution
Step 1: Simplify the argument algebraically
Factor x from numerator and denominator:
x2+2xx2−x=x(x+2)x(x−1)=x+2x−1
Step 2: Expand using the Quotient Property of logarithms
h(x)=ln(x+2x−1)=ln(x−1)−ln(x+2)
Step 3: Differentiate term-by-term using dxd[ln(u)]=uu′
h′(x)=x−11−x+21
Step 4: Combine over a common denominator
h′(x)=(x−1)(x+2)(x+2)−(x−1)=(x−1)(x+2)x+2−x+1=(x−1)(x+2)3
Example 2: Product Rule with General Base Logarithm
Find the derivative of g(x)=3x2log3(x).
Solution
Step 1: Identify the Product Rule structure
Let u=3x2 and v=log3(x).
u′=6x,v′=xln(3)1
Step 2: Assemble the Product Rule
g′(x)=u′v+uv′=(6x)log3(x)+(3x2)(xln(3)1)
Step 3: Simplify algebraic factors
g′(x)=6xlog3(x)+ln(3)3x
Connections & References