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Tony's Intertwingled Memex β€’ Reference Manual

Derivatives of Exponential Functions

Formulas & Definitions
Core Definition

The derivative of an exponential function depends on whether its base is Euler's constant eee or an arbitrary positive real base b>0b > 0b>0 (b≠1b \neq 1b=1): Natural Exponential Function:

ddx[ex]=ex\frac{d}{dx}[e^x] = e^xdxd​[ex]=ex
General Exponential Function:
ddx[bx]=ln⁑(b)bx\frac{d}{dx}[b^x] = \ln(b) b^xdxd​[bx]=ln(b)bx
When the exponent is a differentiable composite function u=g(x)u = g(x)u=g(x), apply the Chain Rule:
ddx[eu]=eududxandddx[bu]=ln⁑(b)bududx\frac{d}{dx}[e^{u}] = e^u \frac{du}{dx} \qquad \text{and} \qquad \frac{d}{dx}[b^{u}] = \ln(b) b^u \frac{du}{dx}dxd​[eu]=eudxdu​anddxd​[bu]=ln(b)budxdu​

Concept Explanation

1. The Unique Geometric Identity of Euler's Number eee

The natural exponential function f(x)=exf(x) = e^xf(x)=ex is the only non-trivial mathematical function whose instantaneous rate of change (derivative) is identical to its current function value for all x∈Rx \in \mathbb{R}x∈R:

ddx[ex]=lim⁑hβ†’0ex+hβˆ’exh=exlim⁑hβ†’0ehβˆ’1h\frac{d}{dx}[e^x] = \lim_{h \to 0} \frac{e^{x+h} - e^x}{h} = e^x \lim_{h \to 0} \frac{e^h - 1}{h}dxd​[ex]=hβ†’0lim​hex+hβˆ’ex​=exhβ†’0lim​hehβˆ’1​
By definition of the natural base eβ‰ˆ2.71828e \approx 2.71828eβ‰ˆ2.71828, the limit lim⁑hβ†’0ehβˆ’1h=1\lim_{h \to 0}\frac{e^h - 1}{h} = 1limhβ†’0​hehβˆ’1​=1, yielding ddx[ex]=exβ‹…1=ex\frac{d}{dx}[e^x] = e^x \cdot 1 = e^xdxd​[ex]=exβ‹…1=ex. Geometrically, the slope of the tangent line to y=exy = e^xy=ex at any point (x0,y0)(x_0, y_0)(x0​,y0​) is equal to its yyy-coordinate y0y_0y0​.

2. General Exponential Base Conversion

For an arbitrary base b>0b > 0b>0, we rewrite the exponential in base eee using inverse properties:

bx=(eln⁑(b))x=exln⁑(b)b^x = \left(e^{\ln(b)}\right)^x = e^{x \ln(b)}bx=(eln(b))x=exln(b)
Applying the Chain Rule to ekxe^{k x}ekx where k=ln⁑(b)k = \ln(b)k=ln(b) is a constant scalar:
ddx[bx]=ddx[exln⁑(b)]=exln⁑(b)β‹…ddx[xln⁑(b)]=bxβ‹…ln⁑(b)\frac{d}{dx}[b^x] = \frac{d}{dx}\left[e^{x \ln(b)}\right] = e^{x \ln(b)} \cdot \frac{d}{dx}[x \ln(b)] = b^x \cdot \ln(b)dxd​[bx]=dxd​[exln(b)]=exln(b)β‹…dxd​[xln(b)]=bxβ‹…ln(b)

3. Power Rule vs. Exponential Rule (The Structural Distinction)

Students frequently confuse the Power Rule with the Exponential Rule. Always inspect the position of the variable:

  • Power Rule: Variable in the base, constant in the exponent: ddx[xn]=nxnβˆ’1\frac{d}{dx}[x^n] = n x^{n-1}dxd​[xn]=nxnβˆ’1 (e.g., ddx[x3]=3x2\frac{d}{dx}[x^3] = 3x^2dxd​[x3]=3x2).
  • Exponential Rule: Constant in the base, variable in the exponent: ddx[bx]=ln⁑(b)bx\frac{d}{dx}[b^x] = \ln(b)b^xdxd​[bx]=ln(b)bx (e.g., ddx[3x]=ln⁑(3)3x\frac{d}{dx}[3^x] = \ln(3)3^xdxd​[3x]=ln(3)3x).
  • Variable Base and Exponent: xxx^xxx requires Logarithmic Differentiation.

Engineering Applications

  • Electrical Engineering (RC and RL Circuits): Transient discharge voltage across a capacitor follows V(t)=V0eβˆ’t/RCV(t) = V_0 e^{-t/RC}V(t)=V0​eβˆ’t/RC. The rate of voltage drop dVdt=βˆ’V0RCeβˆ’t/RC\frac{dV}{dt} = -\frac{V_0}{RC}e^{-t/RC}dtdV​=βˆ’RCV0​​eβˆ’t/RC determines surge protection switching timing.
  • Mechanical & Civil Engineering (Structural Damping): Underdamped mechanical vibrations and seismic building responses decay exponentially according to x(t)=Aeβˆ’ΞΆΟ‰ntcos⁑(Ο‰dt)x(t) = A e^{-\zeta \omega_n t} \cos(\omega_d t)x(t)=Aeβˆ’ΞΆΟ‰n​tcos(Ο‰d​t). Differentiating using Product and Exponential Chain rules yields structural velocity.
  • Aerospace Engineering (Atmospheric Density Decay): Atmospheric density drops exponentially with altitude ρ(z)=ρ0eβˆ’z/H\rho(z) = \rho_0 e^{-z/H}ρ(z)=ρ0​eβˆ’z/H, dictating the rate of aerodynamic heating and drag load during spacecraft reentry.

Example Problems

Example 1: Chain Rule with General Base Exponentials

Find the derivative of y=75x3βˆ’2xy = 7^{5x^3 - 2x}y=75x3βˆ’2x with respect to xxx.

Solution

Step 1: Identify the rule and the inner function The overarching rule is the General Exponential Chain Rule: ddx[bu]=ln⁑(b)buβ‹…uβ€²\frac{d}{dx}[b^u] = \ln(b)b^u \cdot u'dxd​[bu]=ln(b)buβ‹…uβ€². Here, base b=7b = 7b=7 and inner function u=5x3βˆ’2xu = 5x^3 - 2xu=5x3βˆ’2x.

Step 2: Differentiate the inner exponent function

uβ€²=ddx[5x3βˆ’2x]=15x2βˆ’2u' = \frac{d}{dx}[5x^3 - 2x] = 15x^2 - 2uβ€²=dxd​[5x3βˆ’2x]=15x2βˆ’2

Step 3: Assemble the derivative

yβ€²=ln⁑(7)β‹…75x3βˆ’2xβ‹…(15x2βˆ’2)=(15x2βˆ’2)ln⁑(7)75x3βˆ’2xy' = \ln(7) \cdot 7^{5x^3 - 2x} \cdot (15x^2 - 2) = (15x^2 - 2)\ln(7)7^{5x^3 - 2x}yβ€²=ln(7)β‹…75x3βˆ’2xβ‹…(15x2βˆ’2)=(15x2βˆ’2)ln(7)75x3βˆ’2x

Example 2: Product Rule with Natural Exponential Decay

Find the derivative of f(t)=t2eβˆ’0.5tf(t) = t^2 e^{-0.5t}f(t)=t2eβˆ’0.5t and determine where fβ€²(t)=0f'(t) = 0fβ€²(t)=0.

Solution

Step 1: Apply the Product Rule Let u=t2u = t^2u=t2 and v=eβˆ’0.5tv = e^{-0.5t}v=eβˆ’0.5t.

uβ€²=2t,vβ€²=eβˆ’0.5tβ‹…(βˆ’0.5)=βˆ’0.5eβˆ’0.5tu' = 2t, \qquad v' = e^{-0.5t} \cdot (-0.5) = -0.5e^{-0.5t}uβ€²=2t,vβ€²=eβˆ’0.5tβ‹…(βˆ’0.5)=βˆ’0.5eβˆ’0.5t

Step 2: Combine using fβ€²(t)=uβ€²v+uvβ€²f'(t) = u'v + uv'fβ€²(t)=uβ€²v+uvβ€²

fβ€²(t)=(2t)(eβˆ’0.5t)+(t2)(βˆ’0.5eβˆ’0.5t)f'(t) = (2t)(e^{-0.5t}) + (t^2)(-0.5e^{-0.5t})fβ€²(t)=(2t)(eβˆ’0.5t)+(t2)(βˆ’0.5eβˆ’0.5t)

Step 3: Factor out the common exponential and linear terms

fβ€²(t)=eβˆ’0.5t(2tβˆ’0.5t2)=teβˆ’0.5t(2βˆ’0.5t)f'(t) = e^{-0.5t}(2t - 0.5t^2) = t e^{-0.5t}(2 - 0.5t)fβ€²(t)=eβˆ’0.5t(2tβˆ’0.5t2)=teβˆ’0.5t(2βˆ’0.5t)

Step 4: Solve for stationary points where fβ€²(t)=0f'(t) = 0fβ€²(t)=0 Since eβˆ’0.5t>0e^{-0.5t} > 0eβˆ’0.5t>0 for all real ttt:

t=0or2βˆ’0.5t=0β€…β€ŠβŸΉβ€…β€Št=4t = 0 \quad \text{or} \quad 2 - 0.5t = 0 \implies t = 4t=0or2βˆ’0.5t=0⟹t=4


Connections & References

  • Parent Concepts: Derivatives, Logarithmic and Exponential Properties
  • Prerequisites: Power Rule, Chain Rule
  • Inverse Relationship: Derivatives of Logarithmic Functions
  • Linked Engineering Applications: RC Circuit Transient Surge (Electrical Engineering), Atmospheric Density and Aerodynamic Drag (Aerospace Engineering)
  • Course Sessions: Calc-1 Session 08, Calc-1 Session 09